2v+12=8(4-v)

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Solution for 2v+12=8(4-v) equation: 



2v+12=8(4-v)

We move all terms to the left:

2v+12-(8(4-v))=0

We add all the numbers together, and all the variables

2v-(8(-1v+4))+12=0



We calculate terms in parentheses: -(8(-1v+4)), so:

8(-1v+4)

We multiply parentheses

-8v+32

Back to the equation:

-(-8v+32)



We get rid of parentheses

2v+8v-32+12=0

We add all the numbers together, and all the variables

10v-20=0

We move all terms containing v to the left, all other terms to the right

10v=20

v=20/10

v=2

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