2v+2(-4v-2)=4(v-2)

Solution for 2v+2(-4v-2)=4(v-2) equation:

2v+2(-4v-2)=4(v-2)

We move all terms to the left:

2v+2(-4v-2)-(4(v-2))=0

We multiply parentheses

2v-8v-(4(v-2))-4=0


We calculate terms in parentheses: -(4(v-2)), so:

4(v-2)

We multiply parentheses

4v-8

Back to the equation:

-(4v-8)


We add all the numbers together, and all the variables

-6v-(4v-8)-4=0

We get rid of parentheses

-6v-4v+8-4=0

We add all the numbers together, and all the variables

-10v+4=0

We move all terms containing v to the left, all other terms to the right

-10v=-4

v=-4/-10

v=2/5