2v+22=6(v+7)

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Solution for 2v+22=6(v+7) equation: 



2v+22=6(v+7)

We move all terms to the left:

2v+22-(6(v+7))=0



We calculate terms in parentheses: -(6(v+7)), so:

6(v+7)

We multiply parentheses

6v+42

Back to the equation:

-(6v+42)



We get rid of parentheses

2v-6v-42+22=0

We add all the numbers together, and all the variables

-4v-20=0

We move all terms containing v to the left, all other terms to the right

-4v=20

v=20/-4

v=-5

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