2v+3(4v-2)=v+2(2v+4)

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Solution for 2v+3(4v-2)=v+2(2v+4) equation: 



2v+3(4v-2)=v+2(2v+4)

We move all terms to the left:

2v+3(4v-2)-(v+2(2v+4))=0

We multiply parentheses

2v+12v-(v+2(2v+4))-6=0



We calculate terms in parentheses: -(v+2(2v+4)), so:

v+2(2v+4)

We multiply parentheses

v+4v+8

We add all the numbers together, and all the variables

5v+8

Back to the equation:

-(5v+8)



We add all the numbers together, and all the variables

14v-(5v+8)-6=0

We get rid of parentheses

14v-5v-8-6=0

We add all the numbers together, and all the variables

9v-14=0

We move all terms containing v to the left, all other terms to the right

9v=14

v=14/9

v=1+5/9

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