2v+3(v-2)=5v-3(-2v+2)-6

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Solution for 2v+3(v-2)=5v-3(-2v+2)-6 equation: 



2v+3(v-2)=5v-3(-2v+2)-6

We move all terms to the left:

2v+3(v-2)-(5v-3(-2v+2)-6)=0

We multiply parentheses

2v+3v-(5v-3(-2v+2)-6)-6=0



We calculate terms in parentheses: -(5v-3(-2v+2)-6), so:

5v-3(-2v+2)-6

We multiply parentheses

5v+6v-6-6

We add all the numbers together, and all the variables

11v-12

Back to the equation:

-(11v-12)



We add all the numbers together, and all the variables

5v-(11v-12)-6=0

We get rid of parentheses

5v-11v+12-6=0

We add all the numbers together, and all the variables

-6v+6=0

We move all terms containing v to the left, all other terms to the right

-6v=-6

v=-6/-6

v=1

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