2v+32=6(v+6)

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Solution for 2v+32=6(v+6) equation: 



2v+32=6(v+6)

We move all terms to the left:

2v+32-(6(v+6))=0



We calculate terms in parentheses: -(6(v+6)), so:

6(v+6)

We multiply parentheses

6v+36

Back to the equation:

-(6v+36)



We get rid of parentheses

2v-6v-36+32=0

We add all the numbers together, and all the variables

-4v-4=0

We move all terms containing v to the left, all other terms to the right

-4v=4

v=4/-4

v=-1

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