2v+4-2(-4v-2)=4(v-2)

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Solution for 2v+4-2(-4v-2)=4(v-2) equation: 



2v+4-2(-4v-2)=4(v-2)

We move all terms to the left:

2v+4-2(-4v-2)-(4(v-2))=0

We multiply parentheses

2v+8v-(4(v-2))+4+4=0



We calculate terms in parentheses: -(4(v-2)), so:

4(v-2)

We multiply parentheses

4v-8

Back to the equation:

-(4v-8)



We add all the numbers together, and all the variables

10v-(4v-8)+8=0

We get rid of parentheses

10v-4v+8+8=0

We add all the numbers together, and all the variables

6v+16=0

We move all terms containing v to the left, all other terms to the right

6v=-16

v=-16/6

v=-2+2/3

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