2v+4-3(-2v-2)=2(v-3)

Solution for 2v+4-3(-2v-2)=2(v-3) equation:

2v+4-3(-2v-2)=2(v-3)

We move all terms to the left:

2v+4-3(-2v-2)-(2(v-3))=0

We multiply parentheses

2v+6v-(2(v-3))+6+4=0


We calculate terms in parentheses: -(2(v-3)), so:

2(v-3)

We multiply parentheses

2v-6

Back to the equation:

-(2v-6)


We add all the numbers together, and all the variables

8v-(2v-6)+10=0

We get rid of parentheses

8v-2v+6+10=0

We add all the numbers together, and all the variables

6v+16=0

We move all terms containing v to the left, all other terms to the right

6v=-16

v=-16/6

v=-2+2/3