2v+4=5(v+1)-3(v+2)

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Solution for 2v+4=5(v+1)-3(v+2) equation: 



2v+4=5(v+1)-3(v+2)

We move all terms to the left:

2v+4-(5(v+1)-3(v+2))=0



We calculate terms in parentheses: -(5(v+1)-3(v+2)), so:

5(v+1)-3(v+2)

We multiply parentheses

5v-3v+5-6

We add all the numbers together, and all the variables

2v-1

Back to the equation:

-(2v-1)



We get rid of parentheses

2v-2v+1+4=0

We add all the numbers together, and all the variables

5!=0

There is no solution for this equation

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