2v+4v+2v-6v+2v=12

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Solution for 2v+4v+2v-6v+2v=12 equation: 



2v+4v+2v-6v+2v=12

We move all terms to the left:

2v+4v+2v-6v+2v-(12)=0

We add all the numbers together, and all the variables

4v-12=0

We move all terms containing v to the left, all other terms to the right

4v=12

v=12/4

v=3

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