2v+6v=4(4v-4)-7(v-4)

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Solution for 2v+6v=4(4v-4)-7(v-4) equation: 



2v+6v=4(4v-4)-7(v-4)

We move all terms to the left:

2v+6v-(4(4v-4)-7(v-4))=0

We add all the numbers together, and all the variables

8v-(4(4v-4)-7(v-4))=0



We calculate terms in parentheses: -(4(4v-4)-7(v-4)), so:

4(4v-4)-7(v-4)

We multiply parentheses

16v-7v-16+28

We add all the numbers together, and all the variables

9v+12

Back to the equation:

-(9v+12)



We get rid of parentheses

8v-9v-12=0

We add all the numbers together, and all the variables

-1v-12=0

We move all terms containing v to the left, all other terms to the right

-v=12

v=12/-1

v=-12

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