2v-2+2(5v-1)=-3(v+1)

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Solution for 2v-2+2(5v-1)=-3(v+1) equation: 



2v-2+2(5v-1)=-3(v+1)

We move all terms to the left:

2v-2+2(5v-1)-(-3(v+1))=0

We multiply parentheses

2v+10v-(-3(v+1))-2-2=0



We calculate terms in parentheses: -(-3(v+1)), so:

-3(v+1)

We multiply parentheses

-3v-3

Back to the equation:

-(-3v-3)



We add all the numbers together, and all the variables

12v-(-3v-3)-4=0

We get rid of parentheses

12v+3v+3-4=0

We add all the numbers together, and all the variables

15v-1=0

We move all terms containing v to the left, all other terms to the right

15v=1

v=1/15

v=1/15

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