2v-22=6(v-5)

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Solution for 2v-22=6(v-5) equation: 



2v-22=6(v-5)

We move all terms to the left:

2v-22-(6(v-5))=0



We calculate terms in parentheses: -(6(v-5)), so:

6(v-5)

We multiply parentheses

6v-30

Back to the equation:

-(6v-30)



We get rid of parentheses

2v-6v+30-22=0

We add all the numbers together, and all the variables

-4v+8=0

We move all terms containing v to the left, all other terms to the right

-4v=-8

v=-8/-4

v=+2

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