2v-3v2=(2v-2)4v

Solution for 2v-3v2=(2v-2)4v equation:

2v-3v^2=(2v-2)4v

We move all terms to the left:

2v-3v^2-((2v-2)4v)=0


We calculate terms in parentheses: -((2v-2)4v), so:

(2v-2)4v

We multiply parentheses

8v^2-8v

Back to the equation:

-(8v^2-8v)


We get rid of parentheses

-3v^2-8v^2+2v+8v=0

We add all the numbers together, and all the variables

-11v^2+10v=0

a = -11; b = 10; c = 0;
Δ = b2-4ac
Δ = 102-4·(-11)·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-10}{2*-11}=\frac{-20}{-22}
=10/11
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+10}{2*-11}=\frac{0}{-22}
=0
$