2v-5(2v-4)=2v-2(1+6v)

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Solution for 2v-5(2v-4)=2v-2(1+6v) equation: 



2v-5(2v-4)=2v-2(1+6v)

We move all terms to the left:

2v-5(2v-4)-(2v-2(1+6v))=0

We add all the numbers together, and all the variables

2v-5(2v-4)-(2v-2(6v+1))=0

We multiply parentheses

2v-10v-(2v-2(6v+1))+20=0



We calculate terms in parentheses: -(2v-2(6v+1)), so:

2v-2(6v+1)

We multiply parentheses

2v-12v-2

We add all the numbers together, and all the variables

-10v-2

Back to the equation:

-(-10v-2)



We add all the numbers together, and all the variables

-8v-(-10v-2)+20=0

We get rid of parentheses

-8v+10v+2+20=0

We add all the numbers together, and all the variables

2v+22=0

We move all terms containing v to the left, all other terms to the right

2v=-22

v=-22/2

v=-11

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