2v-6+2(2v+9)=-4(v+1)

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Solution for 2v-6+2(2v+9)=-4(v+1) equation: 



2v-6+2(2v+9)=-4(v+1)

We move all terms to the left:

2v-6+2(2v+9)-(-4(v+1))=0

We multiply parentheses

2v+4v-(-4(v+1))+18-6=0



We calculate terms in parentheses: -(-4(v+1)), so:

-4(v+1)

We multiply parentheses

-4v-4

Back to the equation:

-(-4v-4)



We add all the numbers together, and all the variables

6v-(-4v-4)+12=0

We get rid of parentheses

6v+4v+4+12=0

We add all the numbers together, and all the variables

10v+16=0

We move all terms containing v to the left, all other terms to the right

10v=-16

v=-16/10

v=-1+3/5

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