2v-8+3(2v+2)=-4(v+4)

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Solution for 2v-8+3(2v+2)=-4(v+4) equation: 



2v-8+3(2v+2)=-4(v+4)

We move all terms to the left:

2v-8+3(2v+2)-(-4(v+4))=0

We multiply parentheses

2v+6v-(-4(v+4))+6-8=0



We calculate terms in parentheses: -(-4(v+4)), so:

-4(v+4)

We multiply parentheses

-4v-16

Back to the equation:

-(-4v-16)



We add all the numbers together, and all the variables

8v-(-4v-16)-2=0

We get rid of parentheses

8v+4v+16-2=0

We add all the numbers together, and all the variables

12v+14=0

We move all terms containing v to the left, all other terms to the right

12v=-14

v=-14/12

v=-1+1/6

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