2v2+25v-3500=0

Solution for 2v2+25v-3500=0 equation:

2v^2+25v-3500=0

a = 2; b = 25; c = -3500;
Δ = b2-4ac
Δ = 252-4·2·(-3500)
Δ = 28625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{28625}=\sqrt{25*1145}=\sqrt{25}*\sqrt{1145}=5\sqrt{1145}$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-5\sqrt{1145}}{2*2}=\frac{-25-5\sqrt{1145}}{4}
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+5\sqrt{1145}}{2*2}=\frac{-25+5\sqrt{1145}}{4}
$