If it's not what You are looking for type in the equation solver your own equation and let us solve it.
2w(5w+2)=5w+2
We move all terms to the left:
2w(5w+2)-(5w+2)=0
We multiply parentheses
10w^2+4w-(5w+2)=0
We get rid of parentheses
10w^2+4w-5w-2=0
We add all the numbers together, and all the variables
10w^2-1w-2=0
a = 10; b = -1; c = -2;
Δ = b2-4ac
Δ = -12-4·10·(-2)
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:w_{1}=\frac{-b-\sqrt{\Delta}}{2a}w_{2}=\frac{-b+\sqrt{\Delta}}{2a}\sqrt{\Delta}=\sqrt{81}=9w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-9}{2*10}=\frac{-8}{20} =-2/5w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+9}{2*10}=\frac{10}{20} =1/2
| 8x=24-4× | | (x-12)-3=-54 | | u^2+9u+168=12u+56 | | 2u+6=12 | | 5x+15x=-7+11x | | 014-0.03(x+2)=-0.02(1-x) | | 2x+1+2x-3=5x+8 | | 12d^2+39d+30=0 | | 15v-60=-30(20-5v) | | 0.7=x-1.4 | | x/2-36=-2/7-x/2 | | x+0.6=1.9 | | 85=400-15x | | 3x+81-9=-3x | | 3(4x+5)+7=2(3x+23)-4 | | 4(z+1)=-6 | | 4/5-4/5x=36-4/5 | | 3(d+6)=18 | | 3/5(2x+6)=3x+9 | | X+4x+1=3(2x-1) | | 1/3b+25=10 | | 3(x=1)+1+2x=2(2x=2)+x | | 2(x-5)-2=23-3x | | 12z=9 | | 8-5=8(x+4) | | (2/5)x+3=1 | | 3x/6=72 | | 5-x=-x+ | | -3(x+5)+19=13-4x | | F(x)=8x^2+32X+2 | | 3(3g-8)-(4g-2)=-12 | | 2(x+7)-2=47-3x |