2w+(4w+12)=228

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Solution for 2w+(4w+12)=228 equation: 



2w+(4w+12)=228

We move all terms to the left:

2w+(4w+12)-(228)=0

We get rid of parentheses

2w+4w+12-228=0

We add all the numbers together, and all the variables

6w-216=0

We move all terms containing w to the left, all other terms to the right

6w=216

w=216/6

w=36

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