2w+2-2(-3w-3)=2(w-4)

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Solution for 2w+2-2(-3w-3)=2(w-4) equation: 



2w+2-2(-3w-3)=2(w-4)

We move all terms to the left:

2w+2-2(-3w-3)-(2(w-4))=0

We multiply parentheses

2w+6w-(2(w-4))+6+2=0



We calculate terms in parentheses: -(2(w-4)), so:

2(w-4)

We multiply parentheses

2w-8

Back to the equation:

-(2w-8)



We add all the numbers together, and all the variables

8w-(2w-8)+8=0

We get rid of parentheses

8w-2w+8+8=0

We add all the numbers together, and all the variables

6w+16=0

We move all terms containing w to the left, all other terms to the right

6w=-16

w=-16/6

w=-2+2/3

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