2w+2-2(-6w-5)=2(w-3)

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Solution for 2w+2-2(-6w-5)=2(w-3) equation: 



2w+2-2(-6w-5)=2(w-3)

We move all terms to the left:

2w+2-2(-6w-5)-(2(w-3))=0

We multiply parentheses

2w+12w-(2(w-3))+10+2=0



We calculate terms in parentheses: -(2(w-3)), so:

2(w-3)

We multiply parentheses

2w-6

Back to the equation:

-(2w-6)



We add all the numbers together, and all the variables

14w-(2w-6)+12=0

We get rid of parentheses

14w-2w+6+12=0

We add all the numbers together, and all the variables

12w+18=0

We move all terms containing w to the left, all other terms to the right

12w=-18

w=-18/12

w=-1+1/2

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