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2w^2+21w+54=0
a = 2; b = 21; c = +54;
Δ = b2-4ac
Δ = 212-4·2·54
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-3}{2*2}=\frac{-24}{4} =-6 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+3}{2*2}=\frac{-18}{4} =-4+1/2 $
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