2w2+31w+15=0

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Solution for 2w2+31w+15=0 equation:



2w^2+31w+15=0
a = 2; b = 31; c = +15;
Δ = b2-4ac
Δ = 312-4·2·15
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{841}=29$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(31)-29}{2*2}=\frac{-60}{4} =-15 $
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(31)+29}{2*2}=\frac{-2}{4} =-1/2 $

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