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2x(-3+3)-4(x+3)-2=3x(2-2)+3(x-2)+12
We move all terms to the left:
2x(-3+3)-4(x+3)-2-(3x(2-2)+3(x-2)+12)=0
We add all the numbers together, and all the variables
2x0-4(x+3)-(3x0+3(x-2)+12)-2=0
We add all the numbers together, and all the variables
2x-4(x+3)-(3x0+3(x-2)+12)-2=0
We multiply parentheses
2x-4x-(3x0+3(x-2)+12)-12-2=0
We calculate terms in parentheses: -(3x0+3(x-2)+12), so:We add all the numbers together, and all the variables
3x0+3(x-2)+12
We add all the numbers together, and all the variables
3x+3(x-2)+12
We multiply parentheses
3x+3x-6+12
We add all the numbers together, and all the variables
6x+6
Back to the equation:
-(6x+6)
-2x-(6x+6)-14=0
We get rid of parentheses
-2x-6x-6-14=0
We add all the numbers together, and all the variables
-8x-20=0
We move all terms containing x to the left, all other terms to the right
-8x=20
x=20/-8
x=-2+1/2
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