2x(-5x+22)=0

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Solution for 2x(-5x+22)=0 equation:



2x(-5x+22)=0
We multiply parentheses
-10x^2+44x=0
a = -10; b = 44; c = 0;
Δ = b2-4ac
Δ = 442-4·(-10)·0
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1936}=44$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(44)-44}{2*-10}=\frac{-88}{-20} =4+2/5 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(44)+44}{2*-10}=\frac{0}{-20} =0 $

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