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2x(1-4x)=9-x
We move all terms to the left:
2x(1-4x)-(9-x)=0
We add all the numbers together, and all the variables
2x(-4x+1)-(-1x+9)=0
We multiply parentheses
-8x^2+2x-(-1x+9)=0
We get rid of parentheses
-8x^2+2x+1x-9=0
We add all the numbers together, and all the variables
-8x^2+3x-9=0
a = -8; b = 3; c = -9;
Δ = b2-4ac
Δ = 32-4·(-8)·(-9)
Δ = -279
Delta is less than zero, so there is no solution for the equation
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