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2x(1-x)=10
We move all terms to the left:
2x(1-x)-(10)=0
We add all the numbers together, and all the variables
2x(-1x+1)-10=0
We multiply parentheses
-2x^2+2x-10=0
a = -2; b = 2; c = -10;
Δ = b2-4ac
Δ = 22-4·(-2)·(-10)
Δ = -76
Delta is less than zero, so there is no solution for the equation
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