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2x(1200-x)=0
We add all the numbers together, and all the variables
2x(-1x+1200)=0
We multiply parentheses
-2x^2+2400x=0
a = -2; b = 2400; c = 0;
Δ = b2-4ac
Δ = 24002-4·(-2)·0
Δ = 5760000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5760000}=2400$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2400)-2400}{2*-2}=\frac{-4800}{-4} =+1200 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2400)+2400}{2*-2}=\frac{0}{-4} =0 $
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