2x(1x+3)=25

Solution for 2x(1x+3)=25 equation:

2x(1x+3)=25

We move all terms to the left:

2x(1x+3)-(25)=0

We add all the numbers together, and all the variables

2x(x+3)-25=0

We multiply parentheses

2x^2+6x-25=0

a = 2; b = 6; c = -25;
Δ = b2-4ac
Δ = 62-4·2·(-25)
Δ = 236
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{236}=\sqrt{4*59}=\sqrt{4}*\sqrt{59}=2\sqrt{59}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{59}}{2*2}=\frac{-6-2\sqrt{59}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{59}}{2*2}=\frac{-6+2\sqrt{59}}{4}
$