2x(2)+24x-46=0

Solution for 2x(2)+24x-46=0 equation:

2x(2)+24x-46=0

We add all the numbers together, and all the variables

2x^2+24x-46=0

a = 2; b = 24; c = -46;
Δ = b2-4ac
Δ = 242-4·2·(-46)
Δ = 944
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{944}=\sqrt{16*59}=\sqrt{16}*\sqrt{59}=4\sqrt{59}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-4\sqrt{59}}{2*2}=\frac{-24-4\sqrt{59}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+4\sqrt{59}}{2*2}=\frac{-24+4\sqrt{59}}{4}
$