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2x(2)-28x=-98
We move all terms to the left:
2x(2)-28x-(-98)=0
We add all the numbers together, and all the variables
2x^2-28x+98=0
a = 2; b = -28; c = +98;
Δ = b2-4ac
Δ = -282-4·2·98
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{28}{4}=7$
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