If it's not what You are looking for type in the equation solver your own equation and let us solve it.
2x(2)-5+10=0
We add all the numbers together, and all the variables
2x^2+5=0
a = 2; b = 0; c = +5;
Δ = b2-4ac
Δ = 02-4·2·5
Δ = -40
Delta is less than zero, so there is no solution for the equation
| G(25)=6x^2+1 | | (1+r)^10=18.877r+1 | | -14z/3=-28/33 | | -14z=-28/33 | | 3x–8=23 | | 2x2-5+10=0 | | 0.5x32= | | (7x-4)x(2x+3)= | | 49=3(2x-5)-2 | | 4(x+5)+7=35 | | 8x+9=3x+28 | | 2(3x+4)^2/3=32 | | 5y+8/4=7 | | 10-6x–(1–3x)2=0 | | 3w+10=5w+1 | | 4v+7=2v-3 | | 9-x=8,5 | | 1,5+x=5 | | X=88+10y | | 8x+15=2x-27 | | -x+17=-5x+29 | | -5x-6=-4x-11 | | 87+y=99 | | 4.5x-6.5=34 | | −4(2x-3)=28 | | −4(2x-3)=28ç | | 3c+12=180 | | 16*r=12.7 | | 38=-8u+6(u+7) | | 12*r=12.9 | | 7x+4=4x+19x= | | 12/25=15/n |