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2x(2)=10x-21
We move all terms to the left:
2x(2)-(10x-21)=0
We add all the numbers together, and all the variables
2x^2-(10x-21)=0
We get rid of parentheses
2x^2-10x+21=0
a = 2; b = -10; c = +21;
Δ = b2-4ac
Δ = -102-4·2·21
Δ = -68
Delta is less than zero, so there is no solution for the equation
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