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2x(2x+14)=6x-10
We move all terms to the left:
2x(2x+14)-(6x-10)=0
We multiply parentheses
4x^2+28x-(6x-10)=0
We get rid of parentheses
4x^2+28x-6x+10=0
We add all the numbers together, and all the variables
4x^2+22x+10=0
a = 4; b = 22; c = +10;
Δ = b2-4ac
Δ = 222-4·4·10
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-18}{2*4}=\frac{-40}{8} =-5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+18}{2*4}=\frac{-4}{8} =-1/2 $
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