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2x(30-x)=300
We move all terms to the left:
2x(30-x)-(300)=0
We add all the numbers together, and all the variables
2x(-1x+30)-300=0
We multiply parentheses
-2x^2+60x-300=0
a = -2; b = 60; c = -300;
Δ = b2-4ac
Δ = 602-4·(-2)·(-300)
Δ = 1200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1200}=\sqrt{400*3}=\sqrt{400}*\sqrt{3}=20\sqrt{3}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-20\sqrt{3}}{2*-2}=\frac{-60-20\sqrt{3}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+20\sqrt{3}}{2*-2}=\frac{-60+20\sqrt{3}}{-4} $
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