2x(33+3x)-12=4x-13+2

Solution for 2x(33+3x)-12=4x-13+2 equation:

2x(33+3x)-12=4x-13+2

We move all terms to the left:

2x(33+3x)-12-(4x-13+2)=0

We add all the numbers together, and all the variables

2x(3x+33)-(4x-11)-12=0

We multiply parentheses

6x^2+66x-(4x-11)-12=0

We get rid of parentheses

6x^2+66x-4x+11-12=0

We add all the numbers together, and all the variables

6x^2+62x-1=0

a = 6; b = 62; c = -1;
Δ = b2-4ac
Δ = 622-4·6·(-1)
Δ = 3868
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3868}=\sqrt{4*967}=\sqrt{4}*\sqrt{967}=2\sqrt{967}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(62)-2\sqrt{967}}{2*6}=\frac{-62-2\sqrt{967}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(62)+2\sqrt{967}}{2*6}=\frac{-62+2\sqrt{967}}{12}
$