2x(3x+1)+3x(2-2x)+1=17

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Solution for 2x(3x+1)+3x(2-2x)+1=17 equation: 


Simplifying
2x(3x + 1) + 3x(2 + -2x) + 1 = 17

Reorder the terms:
2x(1 + 3x) + 3x(2 + -2x) + 1 = 17
(1 * 2x + 3x * 2x) + 3x(2 + -2x) + 1 = 17
(2x + 6x2) + 3x(2 + -2x) + 1 = 17
2x + 6x2 + (2 * 3x + -2x * 3x) + 1 = 17
2x + 6x2 + (6x + -6x2) + 1 = 17

Reorder the terms:
1 + 2x + 6x + 6x2 + -6x2 = 17

Combine like terms: 2x + 6x = 8x
1 + 8x + 6x2 + -6x2 = 17

Combine like terms: 6x2 + -6x2 = 0
1 + 8x + 0 = 17
1 + 8x = 17

Solving
1 + 8x = 17

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + 8x = 17 + -1

Combine like terms: 1 + -1 = 0
0 + 8x = 17 + -1
8x = 17 + -1

Combine like terms: 17 + -1 = 16
8x = 16

Divide each side by '8'.
x = 2

Simplifying
x = 2

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