2x(3x+30)=360

Solution for 2x(3x+30)=360 equation:

2x(3x+30)=360

We move all terms to the left:

2x(3x+30)-(360)=0

We multiply parentheses

6x^2+60x-360=0

a = 6; b = 60; c = -360;
Δ = b2-4ac
Δ = 602-4·6·(-360)
Δ = 12240
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{12240}=\sqrt{144*85}=\sqrt{144}*\sqrt{85}=12\sqrt{85}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-12\sqrt{85}}{2*6}=\frac{-60-12\sqrt{85}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+12\sqrt{85}}{2*6}=\frac{-60+12\sqrt{85}}{12}
$