2x(3x+4)-19=x(6x-2)+81

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Solution for 2x(3x+4)-19=x(6x-2)+81 equation: 



2x(3x+4)-19=x(6x-2)+81

We move all terms to the left:

2x(3x+4)-19-(x(6x-2)+81)=0

We multiply parentheses

6x^2+8x-(x(6x-2)+81)-19=0



We calculate terms in parentheses: -(x(6x-2)+81), so:

x(6x-2)+81

We multiply parentheses

6x^2-2x+81

Back to the equation:

-(6x^2-2x+81)



We get rid of parentheses

6x^2-6x^2+8x+2x-81-19=0

We add all the numbers together, and all the variables

10x-100=0

We move all terms containing x to the left, all other terms to the right

10x=100

x=100/10

x=10

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