If it's not what You are looking for type in the equation solver your own equation and let us solve it.
2x(3x+5)=52
We move all terms to the left:
2x(3x+5)-(52)=0
We multiply parentheses
6x^2+10x-52=0
a = 6; b = 10; c = -52;
Δ = b2-4ac
Δ = 102-4·6·(-52)
Δ = 1348
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1348}=\sqrt{4*337}=\sqrt{4}*\sqrt{337}=2\sqrt{337}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-2\sqrt{337}}{2*6}=\frac{-10-2\sqrt{337}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+2\sqrt{337}}{2*6}=\frac{-10+2\sqrt{337}}{12} $
| 17a+9a-12a+15a-8a=21a | | 5/8x2/3=0.4166 | | F(x)=3(9)+15 | | 2(3x+3)=52 | | 2(3x+10)=52 | | A={x/4x-1529,x£N} | | x4−10x3+21x2+40x−100=0 | | 2/3=n9 | | X^3+14x-30=0 | | 5(x2+3=35) | | 0.71*(x-14)=18 | | 50-9y=4y/4+4 | | -30x=-210 | | 3y²192=0 | | 0.65x+0.54x=5395.5 | | x3x=11 | | 2x=-3x+12–2x | | -2x=-3x+12–2x | | 3+5g=6+2g | | 5g+4=10+2g | | 9g-10=8g+9 | | 1.7×10^-4=x^2÷0.100-x | | 8e-1=4e+3 | | f(11)=2(11)-7 | | (0.8)x+1.25=(2x)+0.05 | | 5e+2=3e+10 | | 0.8×+1.25=2x+0.05 | | 4e-6=3e+1 | | (x^2+4x)^2-2(x^2+4x)-15=0 | | (x2+4x)2-2(x2+4x)-15=0 | | -13-y=37+9y | | 2x-3+4(x-1)=5 |