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2x(3x+7)-5(3x+7)=0
We multiply parentheses
6x^2+14x-15x-35=0
We add all the numbers together, and all the variables
6x^2-1x-35=0
a = 6; b = -1; c = -35;
Δ = b2-4ac
Δ = -12-4·6·(-35)
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{841}=29$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-29}{2*6}=\frac{-28}{12} =-2+1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+29}{2*6}=\frac{30}{12} =2+1/2 $
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