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2x(3x.6)=45
We move all terms to the left:
2x(3x.6)-(45)=0
We add all the numbers together, and all the variables
2x(+3x.6)-45=0
We multiply parentheses
6x^2-45=0
a = 6; b = 0; c = -45;
Δ = b2-4ac
Δ = 02-4·6·(-45)
Δ = 1080
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1080}=\sqrt{36*30}=\sqrt{36}*\sqrt{30}=6\sqrt{30}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{30}}{2*6}=\frac{0-6\sqrt{30}}{12} =-\frac{6\sqrt{30}}{12} =-\frac{\sqrt{30}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{30}}{2*6}=\frac{0+6\sqrt{30}}{12} =\frac{6\sqrt{30}}{12} =\frac{\sqrt{30}}{2} $
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