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2x(3x-1)+4=2x-1
We move all terms to the left:
2x(3x-1)+4-(2x-1)=0
We multiply parentheses
6x^2-2x-(2x-1)+4=0
We get rid of parentheses
6x^2-2x-2x+1+4=0
We add all the numbers together, and all the variables
6x^2-4x+5=0
a = 6; b = -4; c = +5;
Δ = b2-4ac
Δ = -42-4·6·5
Δ = -104
Delta is less than zero, so there is no solution for the equation
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