2x(3x-1)-8=-2(4x+5)

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Solution for 2x(3x-1)-8=-2(4x+5) equation: 



2x(3x-1)-8=-2(4x+5)

We move all terms to the left:

2x(3x-1)-8-(-2(4x+5))=0

We multiply parentheses

6x^2-2x-(-2(4x+5))-8=0



We calculate terms in parentheses: -(-2(4x+5)), so:

-2(4x+5)

We multiply parentheses

-8x-10

Back to the equation:

-(-8x-10)



We get rid of parentheses

6x^2-2x+8x+10-8=0

We add all the numbers together, and all the variables

6x^2+6x+2=0

a = 6; b = 6; c = +2;
Δ = b2-4ac
Δ = 62-4·6·2
Δ = -12
Delta is less than zero, so there is no solution for the equation

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