2x(3x-1)=28

Solution for 2x(3x-1)=28 equation:

2x(3x-1)=28

We move all terms to the left:

2x(3x-1)-(28)=0

We multiply parentheses

6x^2-2x-28=0

a = 6; b = -2; c = -28;
Δ = b2-4ac
Δ = -22-4·6·(-28)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-26}{2*6}=\frac{-24}{12}
=-2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+26}{2*6}=\frac{28}{12}
=2+1/3
$