2x(3x-1)=4(x.3)

Solution for 2x(3x-1)=4(x.3) equation:

2x(3x-1)=4(x.3)

We move all terms to the left:

2x(3x-1)-(4(x.3))=0

We add all the numbers together, and all the variables

2x(3x-1)-(4(+x.3))=0

We multiply parentheses

6x^2-2x-(4(+x.3))=0


We calculate terms in parentheses: -(4(+x.3)), so:

4(+x.3)

We multiply parentheses

4x

Back to the equation:

-(4x)


We add all the numbers together, and all the variables

6x^2-6x=0

a = 6; b = -6; c = 0;
Δ = b2-4ac
Δ = -62-4·6·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-6}{2*6}=\frac{0}{12}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+6}{2*6}=\frac{12}{12}
=1
$