2x(3x-2)+2(x+2)=(6x*6x)+5

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Solution for 2x(3x-2)+2(x+2)=(6x*6x)+5 equation: 



2x(3x-2)+2(x+2)=(6x*6x)+5

We move all terms to the left:

2x(3x-2)+2(x+2)-((6x*6x)+5)=0

We add all the numbers together, and all the variables

2x(3x-2)+2(x+2)-((+6x*6x)+5)=0

We multiply parentheses

6x^2-4x+2x-((+6x*6x)+5)+4=0



We calculate terms in parentheses: -((+6x*6x)+5), so:

(+6x*6x)+5

We get rid of parentheses

6x*6x+5

Wy multiply elements

36x^2+5

Back to the equation:

-(36x^2+5)



We add all the numbers together, and all the variables

6x^2-2x-(36x^2+5)+4=0

We get rid of parentheses

6x^2-36x^2-2x-5+4=0

We add all the numbers together, and all the variables

-30x^2-2x-1=0

a = -30; b = -2; c = -1;
Δ = b2-4ac
Δ = -22-4·(-30)·(-1)
Δ = -116
Delta is less than zero, so there is no solution for the equation

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