2x(3x-2)-3(1-(2x)2x+3)-x-3/2)=13

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Solution for 2x(3x-2)-3(1-(2x)2x+3)-x-3/2)=13 equation:



2x(3x-2)-3(1-(2x)2x+3)-x-3/2)=13
We move all terms to the left:
2x(3x-2)-3(1-(2x)2x+3)-x-3/2)-(13)=0
We add all the numbers together, and all the variables
2x(3x-2)-3(-2x2x+4)-x-3/2)-13=0
We add all the numbers together, and all the variables
-1x+2x(3x-2)-3(-2x2x+4)-3/2)-13=0
We multiply parentheses
6x^2+6x^2-1x-4x-12-3/2)-13=0
We multiply all the terms by the denominator
6x^2*2)-13+6x^2*2)-13-1x*2)-13-4x*2)-13-12*2)-13-3=0
Wy multiply elements
192x^7=0
We do not support expression: x^7

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