2x(3x-4)-14=0

Solution for 2x(3x-4)-14=0 equation:

2x(3x-4)-14=0

We multiply parentheses

6x^2-8x-14=0

a = 6; b = -8; c = -14;
Δ = b2-4ac
Δ = -82-4·6·(-14)
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-20}{2*6}=\frac{-12}{12}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+20}{2*6}=\frac{28}{12}
=2+1/3
$